-14x^2-2x+16=0

Solution for -14x^2-2x+16=0 equation:

-14x^2-2x+16=0

a = -14; b = -2; c = +16;
Δ = b2-4ac
Δ = -22-4·(-14)·16
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-30}{2*-14}=\frac{-28}{-28}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+30}{2*-14}=\frac{32}{-28}
=-1+1/7
$